Explain the mechanism for the nitration of benzene.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The nitration of benzene is an electrophilic aromatic substitution reaction. The mechanism involves three main steps:
$1$. Generation of the electrophile: The reaction between concentrated $HNO_3$ and concentrated $H_2SO_4$ generates the nitronium ion $(NO_2^+)$,which acts as the electrophile.
$HNO_3 + 2H_2SO_4 \rightarrow NO_2^+ + H_3O^+ + 2HSO_4^-$
$2$. Formation of the carbocation intermediate (arenium ion): The electrophile $(NO_2^+)$ attacks the benzene ring to form a resonance-stabilized carbocation,known as the sigma complex or arenium ion.
$3$. Removal of the proton: The base $(HSO_4^-)$ removes a proton from the $sp^3$ hybridized carbon of the arenium ion to restore the aromaticity of the ring,resulting in the formation of nitrobenzene.

Explore More

Similar Questions

The major product$(s)$ obtained from the following reaction of $1 \ mole$ of hexadeuteriobenzene $(C_6D_6)$ is/are:

What are the major products $X$ and $Y$ respectively in the following set of reactions?

Which one of these is not true for benzene?

Deduce the structure of $(A)$.
$(A) \ C_{8}H_{10}$ $\xrightarrow{KMnO_{4}} (B) \ C_{8}H_{6}O_{4}$ $\xrightarrow[Fe]{Br_{2}} C_{8}H_{5}BrO_{4} (C)$ (one-product only)

Nitrobenzene can be prepared from benzene by using a mixture of conc. $HNO_3$ and conc. $H_2SO_4$. In the nitrating mixture,$HNO_3$ acts as a

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo